Soal Subnetting Dasar

Sebuah IP dengan prefix :
10.10.10.10 /27

Hitunglah:

1. Jumlah Subnet
2. Jumlah Host
3. Nilai Netmask
4. Nilai Blok
5. Pada Posisi mana untuk nilai IP 10.0.0.40 ?

Jawaban:

1. Jumlah Subnet

    2^n = 2 ^(27-8)

           = 2^19

2. Jumlah Host

    n = 27

    m = 32 -27 = 5

    (2^m) - 2 = (2^5) - 2

                    = 32 - 2

                    = 30

3. Nilai netmask

    /27 = 11111111 . 11111111. 11111111. 11100000

          = 255           .   255        .  255         . 224

4.  Nilai Blok

     256 - 224 = 32

5. Posisi Nilai IP 10.0.0.40 berada pada SUBNET 1

    #0 : 10.0.0.0 /27

    #1: 10.0.0.32 /27

       R: 10.0.0.32 -10.0.0.62

       B: 10.0.0.63

    #2: 10.0.0.64 /27

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